Q 12-02-028NEETJEE MainMedium
A parallel plate capacitor with plate separation $d$ has a metal slab of thickness $\dfrac{d}{2}$ inserted between its plates, parallel to them. The capacitance becomes
Answer: (A) $2$ times
Concept. No field inside a metal slab: effective gap $d - t$.
Step 1. Gap. $\dfrac d2$: capacitance doubles.
Answer. $2$ times (Option A).
Solution by Sreeraj P, M.Sc Physics