Q 12-08-106JEE MainJEE Main 2023 (6 Apr, Shift 1)Easy
For the plane electromagnetic wave given by $E=E_0\sin(\omega t-kx)$ and $B=B_0\sin(\omega t-kx)$, the ratio of average electric energy density to average magnetic energy density is
Answer: (D) 1
In an EM wave $\tfrac12\epsilon_0E^2=\dfrac{B^2}{2\mu_0}$ (since $E=cB$), so the ratio is $1$.
Solution by Sreeraj P, M.Sc Physics