Q 12-08-108JEE MainJEE Main 2023 (6 Apr, Shift 2)Easy
The energy density associated with electric field $\vec E$ and magnetic field $\vec B$ of an electromagnetic wave in free space is given by ($\epsilon_0$ – permittivity of free space, $\mu_0$ – permeability of free space)
Answer: (B) $U_E=\dfrac{\epsilon_0E^2}{2},\ U_B=\dfrac{B^2}{2\mu_0}$
$u_E=\tfrac12\epsilon_0E^2$ and $u_B=\dfrac{B^2}{2\mu_0}$.
Solution by Sreeraj P, M.Sc Physics