Q 12-08-067JEE MainJEE Main 2024 (30 Jan, Shift 2)Easy
If the total energy transferred to a surface in time $t$ is $6.48\times10^5\ \text{J}$, then the magnitude of the total momentum delivered to this surface for complete absorption will be:
Answer: (B) $2.16\times10^{-3}\ \text{kg m s}^{-1}$
For complete absorption $$p = \frac Uc = \frac{6.48\times10^5}{3\times10^8} = 2.16\times10^{-3}\ \text{kg m s}^{-1}$$
Solution by Sreeraj P, M.Sc Physics