Q 12-06-021NEETJEE MainMedium
Two coils have mutual inductance $0.05$ H. The current in the first changes as $I = 2\sin(100\pi t)$ A. The maximum emf induced in the second coil is
Answer: (C) $10\pi$ V
$\varepsilon = M\dfrac{dI}{dt} = 0.05 \times 200\pi\cos(100\pi t)$, maximum $10\pi$ V.
Solution by Sreeraj P, M.Sc Physics