Q 12-06-021NEETJEE MainMedium
Two coils have mutual inductance $0.05$ H. The current in the first changes as $I = 2\sin(100\pi t)$ A. The maximum emf induced in the second coil is
Answer: (C) $10\pi$ V
Concept. $\varepsilon = M\dfrac{dI}{dt}$; its maximum comes from the peak of $\dfrac{dI}{dt}$.
Step 1. Differentiate. $\dfrac{dI}{dt} = 200\pi\cos(100\pi t)$.
Step 2. Maximum emf. $0.05 \times 200\pi = 10\pi$ V.
Answer. $10\pi$ V (Option C).
Solution by Sreeraj P, M.Sc Physics