Q 12-06-025NEETJEE MainMedium
A coil of $50$ turns and area $0.04\ \text{m}^2$ rotates at $50$ rad/s about an axis perpendicular to a field of $0.2$ T. The peak emf generated is
Answer: (C) $20$ V
Concept. Peak emf of a rotating coil: $\varepsilon_0 = NBA\omega$.
Step 1. Substitute.
$$\varepsilon_0 = 50 \times 0.2 \times 0.04 \times 50 = 20\ \text{V}$$
Answer. $20$ V (Option C).
Solution by Sreeraj P, M.Sc Physics