Q 12-06-025NEETJEE MainMedium
A coil of $50$ turns and area $0.04\ \text{m}^2$ rotates at $50$ rad/s about an axis perpendicular to a field of $0.2$ T. The peak emf generated is
Answer: (C) $20$ V
$\varepsilon_0 = NBA\omega = 50 \times 0.2 \times 0.04 \times 50 = 20$ V.
Solution by Sreeraj P, M.Sc Physics