Q 12-06-027NEETJEE MainMedium
A square loop of side $10$ cm and resistance $0.5\ \Omega$ is pulled out of a region of uniform field $0.5$ T at a steady $2$ m/s, with one side parallel to the field boundary. The current induced while it is leaving the field is
Answer: (A) $0.2$ A
Only the side still inside the field contributes: $\varepsilon = Blv = 0.5 \times 0.1 \times 2 = 0.1$ V, $I = \dfrac{0.1}{0.5} = 0.2$ A.
Solution by Sreeraj P, M.Sc Physics