A square loop of side $2$ cm is placed in a time varying magnetic field with magnitude as $B = 0.4\sin(300t)$ Tesla. The normal to the plane of loop makes an angle of $60^\circ$ with the field. The maximum induced emf produced in the loop is ______ mV.
Answer: (D) $24$
Concept. $\phi=BA\cos60^\circ$ with $B=B_0\sin\omega t$, so the peak emf is $B_0\omega A\cos60^\circ$.
Step 1. Apply. $0.4\times300\times4\times10^{-4}\times0.5=0.024$ V.
Answer. $24$ mV (Option D).
Solution by Sreeraj P, M.Sc Physics


