Q 12-11-060JEE MainJEE Main 2024 (4 Apr, Shift 1)Easy
Which figure shows the correct variation of the applied potential difference ($V$) with photoelectric current ($i$) at two different intensities of light ($I_1 < I_2$) of the same wavelength?
Answer: (B) see figure
For the same wavelength (same frequency) the stopping potential $V_0$ is the same, so both curves meet the voltage axis at the same point $-V_0$.
A higher intensity gives more photoelectrons per second, so $I_2$ has the larger saturation current. Graph (B) shows exactly this.
Solution by Sreeraj P, M.Sc Physics