Q 12-11-055JEE MainJEE Main 2025 (29 Jan, Shift 1)Easy
If $\lambda$ and $K$ are the de Broglie wavelength and kinetic energy, respectively, of a particle with constant mass, the correct graphical representation for the particle will be
Answer: (B) see figure
$\lambda = \dfrac{h}{\sqrt{2mK}} \Rightarrow K = \dfrac{h^2}{2m\lambda^2}$, so
$$\frac{1}{K} = \frac{2m}{h^2}\lambda^2 \propto \lambda^2$$
The graph of $1/K$ against $\lambda$ is a parabola through the origin, curving upward: graph (2).
Solution by Sreeraj P, M.Sc Physics