Q 12-03-303JEE MainJEE Main 2025 (4 Apr, Shift 1)Easy
The current passing through a wire as a function of time is given as $I(t) = 0.02t + 0.01\ \text{A}$. The charge that will flow through the wire from $t = 1\ \text{s}$ to $t = 2\ \text{s}$ is:
Answer: (D) $0.04\ \text{C}$
$$q = \int_1^2(0.02t + 0.01)\,dt = \left[0.01t^2 + 0.01t\right]_1^2 = 0.01(4 - 1) + 0.01(2 - 1) = 0.04\ \text{C}$$
Solution by Sreeraj P, M.Sc Physics