Q 12-03-188JEE MainJEE Main 2021 (27 Jul, Shift 2)Easy
The resistance of a conductor at $15^\circ\text{C}$ is $16\ \Omega$ and at $100^\circ\text{C}$ is $20\ \Omega$. What will be the temperature coefficient of resistance of the conductor?
Answer: (C) $0.003\ ^\circ\text{C}^{-1}$
$R_2 = R_1\left[1 + \alpha(T_2 - T_1)\right]$:
$$\alpha = \frac{R_2 - R_1}{R_1(T_2 - T_1)} = \frac{20 - 16}{16\times85} = \frac{4}{1360} \approx 0.003\ ^\circ\text{C}^{-1}$$
Solution by Sreeraj P, M.Sc Physics