Q 12-03-193JEE MainJEE Main 2021 (31 Aug, Shift 2)Easy
A resistor dissipates $192$ J of energy in $1$ s when a current of $4$ A is passed through it. Now, when the current is doubled, the amount of thermal energy dissipated in $5$ s is ______ J.
Numerical value type. Enter your answer.
Answer: 3840
$I^2R = 192 \Rightarrow R = \dfrac{192}{16} = 12\ \Omega$.
$$H = (8)^2\times12\times5 = 3840\ \text{J}$$
Solution by Sreeraj P, M.Sc Physics