Q 12-03-063JEE MainJEE Main 2026 (24 Jan, Shift 1)Easy
Two resistors of $100\Omega$ each are connected in series with a 9 V battery. A voltmeter of $400\Omega$ resistance is connected to measure the voltage drop across one of the resistors. The voltmeter reading is ______ V.
Answer: (C) 4
Voltmeter in parallel with one resistor: $\dfrac{100\times400}{500} = 80\ \Omega$.
Total resistance $= 100 + 80 = 180\ \Omega$, current $= \dfrac{9}{180} = 0.05$ A.
Voltmeter reading $= 0.05\times80 = 4$ V.
Solution by Sreeraj P, M.Sc Physics