Q 12-03-024NEETJEE MainEasy
A current of $3.2$ A flows through a wire. The number of electrons crossing any cross-section per second is ($e = 1.6 \times 10^{-19}$ C)
Answer: (A) $2 \times 10^{19}$
$n = \dfrac{I}{e} = \dfrac{3.2}{1.6 \times 10^{-19}} = 2 \times 10^{19}$ per second.
Solution by Sreeraj P, M.Sc Physics