Q 12-12-056JEE MainJEE Main 2024 (30 Jan, Shift 1)Easy
The ratio of the magnitude of the kinetic energy to the potential energy of an electron in the $5^{\text{th}}$ excited state of a hydrogen atom is:
Answer: (C) $\dfrac12$
In any Bohr orbit $K = -\dfrac U2$, so $\dfrac{|K|}{|U|} = \dfrac12$, independent of the state.
Solution by Sreeraj P, M.Sc Physics