Q 12-12-060JEE MainJEE Main 2023 (30 Jan, Shift 1)Easy
Speed of an electron in Bohr's $7^\text{th}$ orbit for Hydrogen atom is $3.6\times10^6\ \text{m s}^{-1}$. The corresponding speed of the electron in $3^\text{rd}$ orbit, in $\text{m s}^{-1}$, is
Answer: (D) $8.4\times10^6$
$v\propto\dfrac1n$, so $v_3=3.6\times10^6\times\dfrac73=8.4\times10^6\ \text{m s}^{-1}$.
Solution by Sreeraj P, M.Sc Physics