Q 12-12-066JEE MainJEE Main 2023 (25 Jan, Shift 2)Medium
The energy levels of an atom are shown in figure. Which one of these transitions will result in the emission of a photon of wavelength $124.1\ \text{nm}$? Given $h=6.62\times10^{-34}\ \text{J s}$.
Answer: (D) D
$$E=\frac{hc}{\lambda}=\frac{6.62\times10^{-34}\times3\times10^8}{124.1\times10^{-9}}\approx1.6\times10^{-18}\ \text{J}=10\ \text{eV}$$
Only transition D ($0\to-10.0\ \text{eV}$) releases $10\ \text{eV}$.
Solution by Sreeraj P, M.Sc Physics