Q 12-07-096JEE MainJEE Main 2022 (25 Jun, Shift 2)Medium
A sinusoidal voltage $V(t) = 210\sin3000t$ volt is applied to a series LCR circuit in which $L = 10\ \text{mH}$, $C = 25\ \mu\text{F}$ and $R = 100\ \Omega$. The phase difference $\Phi$ between the applied voltage and the resultant current will be
Answer: (A) $\tan^{-1}0.17$
$X_L = \omega L = 3000\times0.01 = 30\ \Omega$; $X_C = \dfrac{1}{\omega C} = \dfrac{1}{3000\times25\times10^{-6}} = 13.33\ \Omega$.
$$\tan\Phi = \frac{X_L - X_C}{R} = \frac{16.67}{100}\approx0.17$$
Solution by Sreeraj P, M.Sc Physics