Q 12-07-100JEE MainJEE Main 2022 (25 Jul, Shift 1)Easy
The RMS value of conduction current in a parallel plate capacitor is $6.9\ \mu\text{A}$. The capacitance of this capacitor, if it is connected to a $230\ \text{V}$ AC supply with an angular frequency of $600\ \text{rad s}^{-1}$, will be
Answer: (B) $50\ \text{pF}$
$I = \dfrac{V}{X_C} = V\omega C$:
$$C = \frac{6.9\times10^{-6}}{230\times600} = 5\times10^{-11}\ \text{F} = 50\ \text{pF}$$
Solution by Sreeraj P, M.Sc Physics