Q 12-07-106JEE MainJEE Main 2022 (27 Jul, Shift 1)Easy
A direct current of $4$ A and an alternating current of peak value $4$ A flow through resistance of $3\ \Omega$ and $2\ \Omega$ respectively. The ratio of heat produced in the two resistances in same interval of time will be :
Answer: (B) $3 : 1$
DC: $H_1 \propto I^2R = 16\times3 = 48$.
AC: $I_{\text{rms}}^2 = \dfrac{4^2}{2} = 8$, so $H_2 \propto 8\times2 = 16$.
$$H_1 : H_2 = 48 : 16 = 3 : 1$$
Solution by Sreeraj P, M.Sc Physics