Q 12-07-098JEE MainJEE Main 2022 (26 Jun, Shift 1)Easy
A $110\ \text{V}$, $50\ \text{Hz}$ AC source is connected in the circuit (as shown in figure). The current through the resistance $55\ \Omega$, at resonance in the circuit, will be ______ A.
Numerical value type. Enter your answer.
Answer: 0
$L$ and $C$ are in parallel. At resonance the currents in $L$ and $C$ are equal and opposite, so the parallel combination has (ideally) infinite impedance and draws no current from the source. The current through the $55\ \Omega$ resistor is $0$.
Solution by Sreeraj P, M.Sc Physics