Q 12-07-007NEETNEET 2023Top questionMedium
In a series $LCR$ circuit, the inductance $L$ is $10$ mH, capacitance $C$ is $1\ \mu$F and resistance $R$ is $100\ \Omega$. The frequency at which resonance occurs is :
Answer: (D) $1.59$ kHz
$$\omega_0 = \frac{1}{\sqrt{LC}} = \frac{1}{\sqrt{10 \times 10^{-3} \times 10^{-6}}} = \frac{1}{10^{-4}} = 10^4\ \text{rad/s}$$
$$f_0 = \frac{\omega_0}{2\pi} = \frac{10^4}{6.28} \approx 1592\ \text{Hz} \approx 1.59\ \text{kHz}$$
Solution by Sreeraj P, M.Sc Physics