Q 12-07-012NEETNEET 2020Top questionEasy
A $40\ \mu$F capacitor is connected to a $200$ V, $50$ Hz ac supply. The rms value of the current in the circuit is, nearly :
Answer: (C) $2.5$ A
Concept. $I_{\text{rms}} = \dfrac{V_{\text{rms}}}{X_C}$ with $X_C = \dfrac{1}{2\pi fC}$.
Step 1. Reactance. $X_C = \dfrac{1}{2\pi \times 50 \times 40 \times 10^{-6}} \approx 79.6\ \Omega$.
Step 2. Current. $\dfrac{200}{79.6} \approx 2.5$ A.
Answer. $2.5$ A (Option C).
Solution by Sreeraj P, M.Sc Physics