Q 12-07-012NEETNEET 2020Top questionEasy
A $40\ \mu$F capacitor is connected to a $200$ V, $50$ Hz ac supply. The rms value of the current in the circuit is, nearly :
Answer: (C) $2.5$ A
$$X_C = \frac{1}{2\pi fC} = \frac{1}{2\pi \times 50 \times 40 \times 10^{-6}} \approx 79.6\ \Omega$$
$$I_{rms} = \frac{V_{rms}}{X_C} = \frac{200}{79.6} \approx 2.5\ \text{A}$$
Solution by Sreeraj P, M.Sc Physics