Q 12-07-015NEETJEE MainMedium
The average value of an alternating current $I = I_0\sin\omega t$ over half a cycle (from $0$ to $\pi/\omega$) is
Answer: (B) $\dfrac{2I_0}{\pi}$
$\bar{I} = \dfrac{\omega}{\pi}\int_0^{\pi/\omega} I_0\sin\omega t\,dt = \dfrac{2I_0}{\pi} \approx 0.637I_0$. Over a full cycle the average is zero.
Solution by Sreeraj P, M.Sc Physics