Q 11-05-084JEE MainJEE Main 2024 (9 Apr, Shift 2)Easy
A force $(3x^2 + 2x - 5)\ \text{N}$ displaces a body from $x = 2\ \text{m}$ to $x = 4\ \text{m}$. Work done by this force is ______ J.
Numerical value type. Enter your answer.
Answer: 58
$$W = \int_2^4(3x^2 + 2x - 5)\,dx = \left[x^3 + x^2 - 5x\right]_2^4 = (64 + 16 - 20) - (8 + 4 - 10) = 58\ \text{J}$$
Solution by Sreeraj P, M.Sc Physics