Q 11-05-073JEE MainJEE Main 2024 (6 Apr, Shift 2)Easy
When the kinetic energy of a body becomes 36 times its original value, the percentage increase in the momentum of the body will be
Answer: (D) $500\%$
$p = \sqrt{2mK} \propto \sqrt K$, so the momentum becomes $\sqrt{36} = 6$ times.
Increase $= \dfrac{6p - p}{p}\times100 = 500\%$.
Solution by Sreeraj P, M.Sc Physics