Q 11-05-046NEETJEE MainEasy
The momentum of a body increases by $50\%$. The percentage increase in its kinetic energy is
Answer: (A) $125\%$
$K = \dfrac{p^2}{2m}$, so $\dfrac{K'}{K} = (1.5)^2 = 2.25$. The increase is $125\%$.
Solution by Sreeraj P, M.Sc Physics