Q 11-14-031JEE MainJEE Main 2026 (5 Apr, Shift 1)Easy
A transverse wave on a string is described by $y = 3\sin(36t + 0.018x + \pi/4)$, where $x, y$ are in cm and $t$ in seconds. The least distance between the two successive crests in the wave is ______ cm. (Nearest integer) ($\pi = 3.14$)
Numerical value type. Enter your answer.
Answer: 349
Concept. Successive crests are one wavelength apart, and $\lambda=\dfrac{2\pi}{k}$.
Step 1. Wave number. $k=0.018$ rad cm$^{-1}$.
Step 2. Wavelength. $\lambda=\dfrac{2\times3.14}{0.018}=348.9\approx349$ cm.
Answer. $349$.
Solution by Sreeraj P, M.Sc Physics
