Q 11-14-031JEE MainJEE Main 2026 (5 Apr, Shift 1)Easy
A transverse wave on a string is described by $y = 3\sin(36t + 0.018x + \pi/4)$, where $x, y$ are in cm and $t$ in seconds. The least distance between the two successive crests in the wave is ______ cm. (Nearest integer) ($\pi = 3.14$)
Numerical value type. Enter your answer.
Answer: 349
$k = 0.018$ cm$^{-1}$, and the distance between successive crests is the wavelength:
$$\lambda = \frac{2\pi}{k} = \frac{6.28}{0.018} \approx 349\ \text{cm}$$
Solution by Sreeraj P, M.Sc Physics