Q 11-14-026NEETJEE MainEasy
The intensity of a sound increases by a factor of $100$. The increase in its sound level is
Answer: (B) $20$ dB
$\Delta L = 10\log_{10}\dfrac{I_2}{I_1} = 10\log_{10}100 = 20$ dB.
Solution by Sreeraj P, M.Sc Physics
The intensity of a sound increases by a factor of $100$. The increase in its sound level is
Answer: (B) $20$ dB
$\Delta L = 10\log_{10}\dfrac{I_2}{I_1} = 10\log_{10}100 = 20$ dB.
Solution by Sreeraj P, M.Sc Physics