Q 12-10-016NEETJEE MainMedium
A thin transparent sheet of refractive index $1.5$ placed over one slit of a Young's double slit arrangement shifts the central fringe by $5$ fringes. If the wavelength is $600$ nm, the thickness of the sheet is
Answer: (A) $6\ \mu$m
Extra path $= (\mu - 1)t = n\lambda$: $t = \dfrac{5 \times 600 \times 10^{-9}}{0.5} = 6 \times 10^{-6}$ m.
Solution by Sreeraj P, M.Sc Physics