Q 12-10-015NEETJEE MainMedium
In Young's experiment with two slits of equal intensity $I_0$, the intensity at a point where the path difference is $\dfrac{\lambda}{3}$ is
Answer: (D) $I_0$
Phase difference $\phi = \dfrac{2\pi}{3}$. $I = 4I_0\cos^2\dfrac{\phi}{2} = 4I_0\cos^2 60° = I_0$.
Solution by Sreeraj P, M.Sc Physics