Units and Measurements question for JEE Main (JEE Main 2022 (25 Jul, Shift 1)), with solution

Answer: (A) Electric displacement $\vec D$ and surface charge density

$\vec D = \varepsilon_0\vec E$ has unit $\dfrac{\text{C}^2}{\text{N m}^2}\cdot\dfrac{\text{N}}{\text{C}} = \text{C m}^{-2}$, the same as surface charge density.

Solution by Sreeraj P, M.Sc Physics