Q 11-01-145JEE MainJEE Main 2023 (8 Apr, Shift 1)Easy
Dimension of $\dfrac{1}{\mu_0\epsilon_0}$ should be equal to
Answer: (C) $\text{L}^2\text{T}^{-2}$
$\dfrac{1}{\mu_0\epsilon_0}=c^2$, which has dimensions $\text{L}^2\text{T}^{-2}$.
Solution by Sreeraj P, M.Sc Physics