Q 11-01-109JEE MainJEE Main 2024 (29 Jan, Shift 2)Easy
A physical quantity $Q$ is found to depend on quantities $a$, $b$, $c$ by the relation $Q = \dfrac{a^4b^3}{c^2}$. The percentage errors in $a$, $b$ and $c$ are $3\%$, $4\%$ and $5\%$ respectively. Then, the percentage error in $Q$ is:
Answer: (C) $34\%$
$$\frac{\Delta Q}{Q}\times100 = 4(3\%) + 3(4\%) + 2(5\%) = 12\% + 12\% + 10\% = 34\%$$
Solution by Sreeraj P, M.Sc Physics