The resistance R = (V)/(I), where V = (200 5) V and I = (20 0.2) A. The percentage error in the measurement of R is:

(A) 3.5\%. (Δ R)/(R)×100 = (Δ V)/(V)×100 + (Δ I)/(I)×100 = (5)/(200)×100 + (0.2)/(20)×100 = 2.5\% + 1\% = 3.5\%

Units and Measurements question for JEE Main (JEE Main 2024 (29 Jan, Shift 1)), with solution

Q 11-01-108JEE MainJEE Main 2024 (29 Jan, Shift 1)Easy

The resistance $R = \dfrac{V}{I}$, where $V = (200 \pm 5)\ \text{V}$ and $I = (20 \pm 0.2)\ \text{A}$. The percentage error in the measurement of $R$ is:

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Units and Measurements question for JEE Main (JEE Main 2024 (29 Jan, Shift 1)), with solution

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