Q 11-01-073JEE MainJEE Main 2025 (22 Jan, Shift 1)Easy
If $B$ is magnetic field and $\mu_0$ is permeability of free space, then the dimensions of $(B/\mu_0)$ is
Answer: (C) $[L^{-1}A]$
For a long straight wire $B = \dfrac{\mu_0 I}{2\pi r}$, so
$$\frac{B}{\mu_0} = \frac{I}{2\pi r}$$
This has the dimensions of current per length: $[L^{-1}A]$.
Solution by Sreeraj P, M.Sc Physics