Q 11-01-061JEE MainJEE Main 2026 (4 Apr, Shift 1)Easy
In a screw gauge when the circular scale is given five complete rotations it moves linearly by $2.5$ mm. If the circular scale has $100$ divisions, the least count of screw gauge is ______ mm.
Answer: (D) $5 \times 10^{-3}$
Pitch $= \dfrac{2.5}{5} = 0.5$ mm. Least count $= \dfrac{0.5}{100} = 5 \times 10^{-3}$ mm.
Solution by Sreeraj P, M.Sc Physics