Thermodynamics question for JEE Main (JEE Main 2020 (4 Sep, Shift 2)), with solution

Match the thermodynamic processes taking place in a system with the correct conditions. In the table: $\Delta Q$ is the heat supplied, $\Delta W$ is the work done and $\Delta U$ is change in internal energy of the system.

$$\begin{array}{|l|l|}\hline \text{Process} & \text{Condition} \\ \hline \text{(I) Adiabatic} & \text{(A) } \Delta W = 0 \\ \hline \text{(II) Isothermal} & \text{(B) } \Delta Q = 0 \\ \hline \text{(III) Isochoric} & \text{(C) } \Delta U \neq 0,\ \Delta W \neq 0,\ \Delta Q \neq 0 \\ \hline \text{(IV) Isobaric} & \text{(D) } \Delta U = 0 \\ \hline \end{array}$$