An ideal gas goes from an initial state to a final state. During the process, the pressure of the gas increases linearly with temperature.
A. The work done by the gas during the process is zero.
B. The heat added to the gas is different from the change in its internal energy.
C. The volume of the gas is increased.
D. The internal energy of the gas is increased.
E. The process is isochoric (constant volume process).
Choose the correct answer from the options given below:
Answer: (C) A, D, E only
For an ideal gas $P = \dfrac{nR}{V}T$. Pressure proportional to temperature means $V$ is constant: the process is isochoric (E correct).
- No volume change, so $W = 0$ (A correct) and C is wrong.
- $Q = \Delta U + W = \Delta U$, so B is wrong.
- $P$ increases, so $T$ increases and the internal energy increases (D correct).
A, D, E only.
Solution by Sreeraj P, M.Sc Physics