Q 11-10-079JEE MainJEE Main 2022 (25 Jun, Shift 2)Easy
A copper block of mass $5.0\ \text{kg}$ is heated to a temperature of $500^\circ\text{C}$ and is placed on a large ice block. What is the maximum amount of ice that can melt? [Specific heat of copper: $0.39\ \text{J g}^{-1}\,^\circ\text{C}^{-1}$ and latent heat of fusion of water: $335\ \text{J g}^{-1}$]
Answer: (C) $2.9\ \text{kg}$
Heat given by copper cooling to $0^\circ\text{C}$: $5000\times0.39\times500 = 975000\ \text{J}$.
$$m_{\text{ice}} = \frac{975000}{335}\approx2910\ \text{g}\approx2.9\ \text{kg}$$
Solution by Sreeraj P, M.Sc Physics