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Thermal Properties of Matter question for NEET / JEE Main (EAMCET 2013 (Medical)), with solution

Q 11-10-023NEETJEE MainEAMCET 2013 (Medical)Easy

The temperatures of the two ends A and B of a rod of length $25$ cm and uniform circular cross-section are $100°$C and $0°$C respectively. In the steady state, the temperature at a point $10$ cm from the end B is (ignore heat loss from the curved surface)