Q 11-06-250NEETNEET 2022Top questionEasy
The angular speed of a fly wheel moving with uniform angular acceleration changes from $1200$ rpm to $3120$ rpm in $16$ seconds. The angular acceleration in $\text{rad/s}^2$ is
Answer: (C) $4\pi$
Change in angular speed: $\Delta\omega = (3120 - 1200)\ \text{rpm} = 1920 \times \dfrac{2\pi}{60} = 64\pi\ \text{rad/s}$.
$$\alpha = \frac{\Delta\omega}{t} = \frac{64\pi}{16} = 4\pi\ \text{rad/s}^2$$
Solution by Sreeraj P, M.Sc Physics