Q 11-06-147JEE MainJEE Main 2021 (31 Aug, Shift 1)Easy
Angular momentum of a single particle moving with constant speed along a circular path:
Answer: (B) remains same in magnitude and direction
About the centre, $\vec L = m\vec r\times\vec v$ has magnitude $mvr$, which is constant, and its direction is always perpendicular to the plane of the circle.
So $\vec L$ stays the same in magnitude and direction (there is no torque about the centre).
Solution by Sreeraj P, M.Sc Physics