Q 11-06-138JEE MainJEE Main 2022 (26 Jul, Shift 2)Easy
The radius of gyration of a cylindrical rod about an axis of rotation perpendicular to its length and passing through the center will be ______ m. Given, the length of the rod is $10\sqrt3\ \text{m}$.
Numerical value type. Enter your answer.
Answer: 5
$I = \dfrac{ML^2}{12} = Mk^2\Rightarrow k = \dfrac{L}{\sqrt{12}} = \dfrac{10\sqrt3}{2\sqrt3} = 5\ \text{m}$ (treating the rod as thin).
Solution by Sreeraj P, M.Sc Physics