Q 12-14-161JEE MainJEE Main 2021 (27 Aug, Shift 2)Easy
For a transistor $\alpha$ and $\beta$ are given as $\alpha = \frac{I_C}{I_E}$ and $\beta = \frac{I_C}{I_B}$. Then the correct relation between $\alpha$ and $\beta$ will be:
Answer: (C) $\beta = \frac{\alpha}{1-\alpha}$
$I_E = I_B + I_C$, so
$$\beta = \frac{I_C}{I_E - I_C} = \frac{I_C/I_E}{1 - I_C/I_E} = \frac{\alpha}{1 - \alpha}$$
Solution by Sreeraj P, M.Sc Physics