Q 12-14-107JEE MainJEE Main 2022 (24 Jun, Shift 2)Easy
In the given circuit, the value of current $I_L$ will be ______ mA. (When $R_L = 1\ \text{k}\Omega$)
Numerical value type. Enter your answer.
Answer: 5
Without the Zener, the voltage across $R_L$ would be $10\times\dfrac{1000}{1800}\approx5.6\ \text{V} > 5\ \text{V}$, so the Zener conducts in breakdown and holds the load voltage at $5\ \text{V}$.
$$I_L = \frac{5\ \text{V}}{1\ \text{k}\Omega} = 5\ \text{mA}$$
Solution by Sreeraj P, M.Sc Physics