Semiconductor Electronics question for JEE Main (JEE Main 2024 (27 Jan, Shift 2)), with solution

Answer: (B) $\begin{array}{ccc} A & B & Y \\ \hline 0 & 0 & 0 \\ 0 & 1 & 1 \\ 1 & 0 & 1 \\ 1 & 1 & 0 \end{array}$

Upper AND gate: inputs $A$ and $\bar B$, output $A\bar B$.

Lower AND gate: inputs $\bar A$ and $B$, output $\bar A B$.
$$Y = A\bar B + \bar A B$$
This is XOR: $Y = 0, 1, 1, 0$ for $AB = 00, 01, 10, 11$.

Solution by Sreeraj P, M.Sc Physics