Q 12-14-036NEETJEE MainMedium
When the forward voltage across a diode is increased from $0.70$ V to $0.75$ V, the current rises from $10$ mA to $20$ mA. The dynamic resistance of the diode in this range is
Answer: (B) $5\ \Omega$
$r_d = \dfrac{\Delta V}{\Delta I} = \dfrac{0.05}{0.010} = 5\ \Omega$.
Solution by Sreeraj P, M.Sc Physics