Q 12-09-124JEE MainJEE Main 2023 (6 Apr, Shift 1)Easy
A monochromatic light wave with wavelength $\lambda_1$ and frequency $\nu_1$ in air enters another medium. If the angle of incidence and angle of refraction at the interface are $45^\circ$ and $30^\circ$ respectively, then the wavelength $\lambda_2$ and frequency $\nu_2$ of the refracted wave are
Answer: (D) $\lambda_2=\dfrac1{\sqrt2}\lambda_1,\ \nu_2=\nu_1$
$\mu=\dfrac{\sin45^\circ}{\sin30^\circ}=\sqrt2$. The frequency is unchanged and $\lambda_2=\dfrac{\lambda_1}{\mu}=\dfrac{\lambda_1}{\sqrt2}$.
Solution by Sreeraj P, M.Sc Physics